Unformatted text preview: 0.0683 slug (= 2.2 lb m ) = 1 kg 3.281 ft = 1 m 0.224 lb (= 0.102 kg f ) = 1 N 1.8 o R = 1.0 o K ( _ ) o R = ( _ ) o F + 460 ( _ ) o K = ( _ ) o C + 273 p S = 2116 lb/ft 2 = 1.013 x 10 5 N/m 2 = 1 atm T S = 59 o F = 15 o C = 519 o R = 288 o K ρ s = 0.002378 lb sec 2 /ft 4 = 1.225 kg/m 3 μ s = 3.7373 x 107 lb sec/ft 2 = 1.7894 x 105 kg/(m sec) 1 g (h h ) RT 1 p e p = g aR 1 1 p T ( ) p T = E G E G R h ( )h R h = + a s = 1116 ft/s = 340 m/s R air = 1716 ft lb/(slug o R) = 287 N m/(kg o K) γ air = 1.4 p c R 1 γ = γ  c p, air = 6006 ft lb/(slug o R) = 1004 N m/(kg o K) g o = 32.2 ft/s 2 = 9.81 m/s 2 F = G M m / R 2 T(h) = 15  .0065h (T is in o C, h is in meters) G = 6.67 x 1011 m 3 /(kg s 2 ) dp =  ρ g dh G dp =  ρ g o dh p 2 p 1 =  ρ g (h 2 h 1 ) M=V/a a 2 = γ RT p = ρ RT ρ AV = m & = constant 2 2 1 2 1 2 V V p p constant 2 2 ρ ρ + = + = F ma = ¡ ¡ 2 2 1 2 p 1 p 2 p V V c T c T c T 2 2 + = + = 2 1 1 T 1 1 M T 2 γ  = + 1 2 2 2 1 1 1 p T p T γ γ γ & ¡ & ¡...
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 Fall '05
 Strganac
 Aerospace Engineering, Trigraph, p1, kg oK, RT p1, ft lb/

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