Homework7

# Homework7 - Homework 7 Answers 95.657 Electromagnetic...

This preview shows pages 1–2. Sign up to view the full content.

Homework 7 Answers, 95.657 Electromagnetic Theory I Dr. Christopher S. Baird, UMass Lowell Jackson 3.14 A line charge of length 2 d with a total charge Q has a linear charge density varying as ( d 2 z 2 ), where z is the distance from the midpoint. A grounded, conducting, spherical shell of inner radius b > d is centered at the midpoint of the line charge. (a) Find the potential everywhere inside the spherical shell as an expansion in Legendre polynomials. SOLUTION: This problem includes both a charge distribution and a boundary condition. We must use the Green function method to include both. The Green function method solution for Dirichlet boundary conditions is:  x = 1 4  0  x ' G D d 3 x ' 1 4 d G D d n ' da ' In this particular case, the boundary condition states that the potential is zero on the spherical surface. This causes the entire surface integral in the Green function solution to equate to zero. The solution is then:  x = 1 4  0  x ' G D d 3 x ' The charge density that satisfies the description above is:  r , , = 3 Q 8 d 3 d 2 r 2 r 2 [ cos − 1  cos  1 ] if r < d and  r , , = 0 r > d The r 2 in the denominator was required to convert the linear charge density into spherical coordinates. The constants out front were found by integrating over all space and setting the result equal to the total

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 03/21/2012 for the course PHY 2030 taught by Professor Avery during the Spring '11 term at University of Florida.

### Page1 / 3

Homework7 - Homework 7 Answers 95.657 Electromagnetic...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online