Jennifer First try assesssment 3-1.pdf - Southern New Hampshire University 3-3 Module Three Problem Set 2:26 PM[PRINT MAT-140-X1355 20EW1 Precalculus

# Jennifer First try assesssment 3-1.pdf - Southern New...

• 17
• 100% (5) 5 out of 5 people found this document helpful

This preview shows page 1 - 6 out of 17 pages.

9/20/20, 2:26 PMSouthern New Hampshire University - 3-3 Module Three Problem SetPage 1 of 17[PRINT]MAT-140-X1355 20EW1 Precalculus, 3-3 Module Three Problem Set Jennifer Lobe, 9/20/20 at 2:59:36 PM EDTQuestion1:Score 3/3Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or produof logs.ln14kEnclose arguments of functions in parentheses and include a multiplication sign between terms. Fexample, c* ln(h).ln14k=Your responseCorrect response-2kln(2)-2*k*ln(2)Auto gradedGrade:1/1.0 A+ 100% Total grade: 1.0×1/1 = 100%Feedback:We can expand by applying the Quotient Rule.()()!!
9/20/20, 2:26 PMSouthern New Hampshire University - 3-3 Module Three Problem SetPage 2 of 17ln14k= ln(1)ln 4kApply the Quotient Rule.= 0ln22kSimplify by writing 4as 22.=ln22kSimplify.=2kln(2)Apply the Power Rule.Question2:Score 3/6Use the properties of logarithms to expand the logarithm as much as possible. Rewrite texpression as a sum, difference, or product of logs.logx3y6logx3y6=Your responseCorrect response3 log(x)23 log(y)3/2*log(x)-3*log(y)Auto gradedGrade:3/3.0 A+ 100% Show your work and explain, in your own words, how you arrived at your answer.()()(())()()()!
9/20/20, 2:26 PMSouthern New Hampshire University - 3-3 Module Three Problem SetPage 3 of 17Rewrite log1/2(log(x^3)+log(y^-6))Expand 3 outside the logarithm.1/2(3log(x)+log(y^6))Expand log by moving 6 outside the logarithm.1/2(3log(x)6log(y))Apply the distributive property.1/2(3log(x))+1/2(6log(y))Multiply 1/2(3log(x))Cancel the common factor of 2Rewrite the expression.3log(x)/23log(y)Keywords:Partial Grades: Ungraded Grade:0/3.0 F 0%Total grade: 1.0×3/6 + 0.0×3/6 = 50% + 0%Feedback:First we rewrite the argument as a power to getlogx3y6= logx3y612.Using the properties of exponents we havelogx3y612= logx32y3.+"()(())(())()
9/20/20, 2:26 PMSouthern New Hampshire University - 3-3 Module Three Problem SetPage 4 of 17Since the argument is factored completely, we can write the equivalent equation by summing tlogarithms of each factor.logx32y3=logx32+ logy3Applying the power rule we have logx32+ logy3=32log(x)3log(y).Question3:Score 0/4Condense the expression to a single logarithm using the properties of logarithms.log (x)12log (y) + 5 log (z)Enclose arguments of functions in parentheses and include a multiplication sign between terms. Fexample, c* log(h).log (x)12log (y) + 5 log (z) =Your responseCorrect responselogxz5y12log(x*z^5/sqrt(y))()()()()()()
9/20/20, 2:26 PMSouthern New Hampshire University - 3-3 Module Three Problem SetPage 5 of 17Auto gradedGrade:0/1.0 F 0% Total grade: 0.0×1/1 = 0%Feedback:
• • • 