{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

mthsc810-lecture13-1x2

mthsc810-lecture13-1x2 - MthSc 810 Mathematical Programming...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
MthSc 810: Mathematical Programming Lecture 13 Pietro Belotti Dept. of Mathematical Sciences Clemson University October 13, 2011 Reading for today: Section 4.5 Reading for Oct. 20: Section 4.6-4.7 Midterm 2: November 1, 2011, 2pm Dual feasibility Consider a primal LP and its dual: max c x min u b s . t . A x b s . t . u A c x 0 u 0 Add slack variables to the primal, surplus 1 variables to the dual. max c x min u b s . t . A x + x = b s . t . u A u = c x , x 0 u , u 0 Note: primal ≡ − min {− c x : A x + x = b , ( x , x ) 0 } . 1 Called “surplus” because we subtract from the left-hand side.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Example max 3 x 1 + 2 x 2 + x 3 min 4 u 1 + 6 u 2 s . t . x 1 + x 2 + x 3 4 s . t . u 1 + 2 u 2 3 2 x 1 + x 2 + 3 x 3 6 u 1 + u 2 2 x 1 , x 2 , x 3 0 u 1 + 3 u 2 1 u 1 , u 2 0 become max 3 x 1 + 2 x 2 + x 3 ( ≡ − min 3 x 1 2 x 2 x 3 ) s . t . x 1 + x 2 + x 3 + x 4 = 4 2 x 1 + x 2 + 3 x 3 + x 5 = 6 x 1 , x 2 , x 3 , x 4 , x 5 0 min 4 u 1 + 6 u 2 s . t . u 1 + 2 u 2 u 3 = 3 u 1 + u 2 u 4 = 2 u 1 + 3 u 2 u 5 = 1 u 1 , u 2 , u 3 , u 4 , u 5 0 Primal and dual dictionaries Make the primal a min problem. Then for B = { 4 , 5 } , x 4 = 4 x 1 x 2 x 3 x 5 = 6 2 x 1 x 2 3 x 3 z = 3 x 1 2 x 2 x 3 . Feasible 2 solution ( 4 , 6 0) but not optimal ( 3 , 2 , 1 < 0). In the dual, consider the basis ( u 3 , u 4 , u 5 ) and the dictionary u 3 = 3 + u 1 + 2 u 2 u 4 = 2 + u 1 + u 2 u 5 = 1 + u 1 + 3 u 2 w = 4 u 1 6 u 2 . Infeasible solution ( 3 , 2 , 1 < 0). If it wasn’t, it would be optimal (the reduced costs are 4 , 6 0). 2 Or better, primalfeasible .
Image of page 2
Primal and dual dictionaries Change indices of the dual variables so that dual surplus variables have indices 1 , 2 . . . , n , same as primal original variables: min 4 u 4 + 6 u 5 s . t . u 4 + 2 u 5 u 1 = 3 u 4 + u 5 u 2 = 2 u 4 + 3 u 5 u 3 = 1 u 4 , u 5 , u 1 , u 2 , u 3 0 . . . and clear up the link between primal and dual dictionaries: x 4 = 4 x 1 x 2 x 3 x 5 = 6
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern