ReadingQuestions_9_Chp_5.6 - 3 Under the conditions of...

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Chemical Engineering 374 Fall 2011 Reading Questions 9—Chapter 5.6 Name ________________________________________________________ 1. In the derivation of the steady-state mechanical energy equation, how were the internal energy and heat-transfer terms converted into a mechanical energy “loss” and what does that mean in terms of the definition of that loss? 2. In your own words, why is the “kinetic energy correction factor” needed?
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Unformatted text preview: 3. Under the conditions of Example 5-12, what magnitude (approximate) temperature rise would you expect if the water was recirculated through the pump 100 times? 4. Examples 5-13 and 5-15 have similar geometries, but the flow directions differ. How was the mechanical energy equation formulated in each case to specify the direction?...
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