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Unformatted text preview: . We have A T A = 4 12 12 46 A T b = 4 9 and solving this gives ( , ) = (19 / 10 ,3 / 10). (4) Let A = (2 , 7 ,5). Find the point P on the plane : x2 y + z = 4 such that AP is perpendicular to the plane. Solution. First note that n = (1 ,2 , 1) T is normal to the plane , so the point P such that AP is perpendicular is given by the intersection of the line ` ( ) = a + n and , where A = (2 , 7 ,5) T . Solving the equation (2 + )2(72 ) + (5 + ) = 4 gives = 7 / 2, so P is the point with coordinate vector (11 / 2 , ,3 / 2) T . 1...
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This document was uploaded on 03/19/2012.
 Three '11

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