{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

GAS LAP - Samuel Castrejon Period 1 12 November 2011 Gas...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Samuel Castrejon Period 1 12 November 2011 Gas Lab: Reaction of Metal with Acid Data: Table 1. Volume of Hydrogen Gas measured at Room Temperature for Calcium Metal and Nitric Acid Trial 1 Trial 2 Trial 3 Average Volume Volume of H 2 26.8 mL 28.1 mL 21.5 mL 25.5 mL Ca + 2HNO 3 Ca(NO 3 ) 2 + H 2 10/25 (Calcium: Trial 1) T (Room)= 21.75°C = 294.75 K P (Room) = 759 mmHg P (H 2 O) = x___ = 19.8 mmHg = 19.58 mmHg 21.75°C 22.0°C P (H 2 ) = P (Room) P (H 2 O)= 759 – 19.58 = 739.42 mmHg = 0.973 ATM Moles of Calcium: n = (.973 ATM)(.025L) / (.0821 L*ATM / mol*K)(294.75K) = 0.00101 mol Ca Grams of Calcium 0.00101 mol Ca x 40.708 grams Ca = 0.0411g Ca required 1 mol Ca Results = 26.8 mL H 2 10/27 (Calcium; Trials 2 and 3) T (Room) = 22.35°C = 295.25 K P (Room) = 767 mmHg P (H 2 O) = x___ = 19.8 mmHg = 20.12 mmHg 22.35°C 22.0°C
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
P (H 2 ) = P (Room) P (H 2 O) = 767 – 20.12 = 746.89 mmHg = 0.983 ATM Moles of Calcium: n = (.983 ATM)(.025L) / (.0821 L*ATM / mol*K)(295.25K) = 0.00101 mol Ca Grams of Calcium 0.00101 mol Ca x 40.708 grams Ca = 0.0411g Ca required 1 mol Ca Results = 28.1 and 21.5 mL H 2 Percent Error |25.0 mL - 25.5 mL| x 100 = 2.00 % error 25.0 mL Table 2 Volume of Hydrogen Gas Measured at Room Temperature for Magnesium Metal and Hydrochloric Acid Trial 1 Trial 2 Trial 3 Average Volume Volume of H 2 31.5 mL 30.0 mL 19.8 mL 27.1 mL Mg + 2HCl MgCl 2 + H 2 Calculations: 10/31 (Magnesium; Trials 1, 2, 3) T (Room) = 22.05°C = 295.05 K
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern