2011 Exam 1 Crib

2011 Exam 1 Crib - Chemistry 24100 Spring 2011 Exam 1 Name...

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Unformatted text preview: Chemistry 24100 Spring 2011 Exam 1 Name C, (E 11 TA Section 1. You are responsible for all information on this page. 2. Show all work on the exam, and write answers in ink. Clearly indicate your answer and mark through any writing that should be ignored in grading. 3. There are four questions and one bonus question. You should also have a Periodic Table. Potentially Helpful Information E = -(l3.6 ZZ)/(n)2 Energies of a hydrogen-like atom in eV E = by = hc/k A hydrogenic orbital has n. — 1 total nodes of which a are non-radial nodes. 0 = 2.998 x108m s" h = 6.626 x 1034.13 mass e' = 9.1094 x 10'31 kg 1 1 molecule"1 = 6.242 x 1018 eV molecule"1 Slater’s Rules Zeff = Z - 20i o.- = 1.00 for e' in (n—2) shell or lower 6; = 0.85 for e" in (n—l) shell oi = 0.35 for e' in same (ns,np) shell 01 = 0.00 for e' in (n+1) shell Problem 1 . Problem 2. Problem 3. Problem 4. Bonus Total /20 /20 /20 /20 /2 /80 $323.. 33% "mos. up: .0 23:5: $2.: 3: 2m $355.3 E 33:32“ .5. .3? 59: .mm. .3? 5:. :3? EA v .3? 53 an? 3mm 2Q _ mama 3 oz 32 En. mu 6 .a .5 :3. a; a: a an p.» m3 we; 2: 03 mm mm .8 wm mm em 8 «m E om 3.3.05 3.3: 3.3 :32. 93.: 2......qu 92.: «392 $53 $5.: .2: :3: 83: ~33 3 a» E» a o: E a» R... Em Eu 3. E nu .fifiif 2 2. ma 8 S 8 mm 3 mm B 8 mm mm as. an”. am. hi mm C mm mm B .3... an. 5:. $32 2.3“ is «32 “8% SE 22 “.8. 32 SE mag .35 .3: «:2 83: 5. a on. .5 .E z m: 3 E = me o: 3 E E .3 am no mm mm en mm an S 8 an an R 2 mu 2. mm NR 8 mm mm a2: 38% 8.3 9:: 3w: “2: ea: 23.: $2 832 2:2 .8. a? was NS... 3% 3.3 Ea ox _ a» an E... z. 8 3 E .E a: a. a: a: .N » a a: 3 mm um 3.. cm 3 3 D. we 3 3 3 we 3 3 mm mm mm 3.3 m8: 3.: 2a.: 3: :2 as 3.3 :3 ~23.“ 3.3 83.3 fig 23.. 3.: am: 8.3 33” .x 5 cm 2 no no cw 6 _z 8 a :2, a > .: um 3 x mm mm cm mm wm an an an aw R 3 mm «a mm mm «a on Q 33» 5mm .82 33.2 max .38 m: m H m5» m? m > m3 m5 an: a8: 3. 5 m m m _< _ me a: 3 2 S a 2 2 .fi 5 "2.8 $8.2 2.3.2 55.: :52 02 m 0 Z 0 m 2 m m h m m 386 EH). ¢H> t L? <>H < HE a: u ~29; l. (20 points.) Orbitals of the hydrogen atom. A. The 219(2) orbital of the hydrogen atom has one angular node. Sketch a contour of the orbital on the axes provided below and shade appropriately. B. The Figure below depicts plots of R2 and 4713'2 R2 for a 3d orbital of the hydrogen atom. The scale is such that the net probability of finding the electron is unity for each curve. Identify A and B, and briefly explain why the plots maximize in different places. Finally, in units of the Bohr radius, predict the most probable value of r for a 3d electron of the hydrogen atom. ' 2.. 3/ 2 R K ill Ll’rtr K l‘l MWX'itfilitAg-l Cd. Ellie {ball algal“ agar; MW pebble defile/m. U3 M33143 GEM/3 We?) _ B MENU/Macs ml ((6 (walks ‘th W Walla Ulla a r .-{a '3 enema-A ll “kw” lQVLQdA it” laeecmgx a we law/Lea 4g a Vat/Lama, an. t‘ Probabiiity per unit measure C. Sketch the radial distribution function of a 33 orbital on the Figure presented in part B. Show the important ways it differs from the plot for the 3d wave function. 331 R30 3 ’2 balm/h 2. (20 points.) Atomic structure and periodicity. A. Identify the atom associated with each of the following electron configurations: i) [Kr]5524d3 .25.; W0 Ni) ii) [Ne1352 2-2» ['2 B. Write a proper equation, and define the electron affinity (EA) of atom E(g). ej'nerpgsvb kiwi. with“ {DA 61"" Aha/rah V‘s (Ln/1 6&3 wt , lr‘ C9. 3 bliter t Ga. '87. F“ m ELS) 1. a" E A 3. IE“ C‘ The electron affinity of N(g) is about zero, but 0(g) has BA = 1.5 eV. Briefly describe two effects that help explain the difference in behavior. l _ E‘va 2th” Ilaecaufin’ egg [\MQP-titbl Screach O cerium flinch gleam imam, , <3” paw.me i he Eat-J4. ‘ " ~ - " a 'ljau’ttehqt 3‘ . The. 6/6“ ,r'tQ-Pi’kll/Es‘cfiffl W N35)” W Alla @1le _ w E I bmcwtt cg! 29') (a Uv’t il’w‘. Emlfl f: (5&5 “his W fillfl Glfixh D. It may come as a surprise to learn that the EA of S(g) is greater than that of 0(g). Explain why is this observation a bit surprising, and giv_e a plausible explanation. lllblvlz‘l is caste/L 1%“ {R 2 p J Settles/tax Baler} m e? e a, 3? lie hit/106m: . {IS (fiesta "-l‘ 23 wflpflm a (taliuawlflcfia (L :‘lfit ‘56) tLlG‘yl‘el t3 l5 [ML-fit) g m W3 {in mil-Alma 30 tile 6/6“ Atgwlwg Earn a see finial 5 Milk 1:3 glflkLi/lfi/L' 3. (20 points) Groups I and II. A. Complete and balance the following reactions: i. Mg(s) + Rum) mil» {thLb—llll T’“ [‘11. % ii. Calif) + éngom —> BCilOllll 'i‘ AWE B. Identify the anion in each of the following compounds, and draw an electron-dot (Lewis) structure for the anion. e3 i a i t i. Ko2 01 gal/nequ (lo : Q “”” ‘ r a i ‘ ii. LiNHg ll umtlii t l H C. Identify a/the metal for each of the following: i. A group I metal that combines with 02(g) and N2(g) to give an oxide and a nitride, respectively. Write formulas for the two products. Lt Z?) L €le ii. A group 11 metal that combines with 02(g) to give M0205). Name the product. B “30?, WWW Wfi/tja 4. (20 points) Draw Lewis structures and predict the geometry/structure for parts A and B. For C-D give an atom consistent with the molecule or ion described. Show your reasoning. A c032" /O\ l‘ / L3 / 0/ x “at B SO; J L (B / / 5:38 0 / C. XF3 (T—shaped molecule; predict X) i3 ids-«F “F D. X132 (linear molecule; predict X) {1, (‘ rt" 4 Viz-~— K€ MP (fl—"f "’gfim—h: E. XE;+ (saw horse/see-saw ion; predict X) if 4 if“ 10:in P Bonus. (2 points) Describe with a picture what solvated eiectrons are gag an easy way to prepare a solution containing them. \ X/ \ (i I Misfit Wire) “5' Masai] Grail) ...
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2011 Exam 1 Crib - Chemistry 24100 Spring 2011 Exam 1 Name...

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