Problem set 3 Crib 2011 - Chapter 2: Exercises 2.3b,...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 2 : Exercises 2.3b, 2.15(C2+), 2.19b, 2.21a-b 2.3b Square Planar 2.15 C 2 - 1 g 2 1 u 2 1 u 4 2 g 1 HOMO is 2 g Bonding sigma orbital C 2 + 1 g 2 1 u 2 1 u 3 HOMO is 1 u Bonding Pi orbitals 2.19b N 2 + e - adds an electron into an antibonding orbital. This decreases the bond order from 3 to 2.5 and therefore will increase the bond distance.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
I. Rationalize the bond length order O 2 + < O 2 < O 2 - with an MO scheme, and predict the magnetic properties of each species (paramagnetic or diamagnetic). Use Figure 2.17 to see the MO scheme of O 2 . The cation O 2 + has 11 electrons and a bond order of 2.5. O 2 has 12 electrons and a bond order of 2. The anion O 2 - has 13 electrons and a bond order of 1.5. The lengths of the bonds have the order of O 2 + < O 2 < O 2 - because the bonds are getting weaker as electrons are added and as a result longer. All the complexes are paramagnetic as they have at least 1 unpaired electron. II.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/20/2012 for the course CHM 24100 taught by Professor Professordavidr.mcmillin during the Spring '10 term at Purdue University-West Lafayette.

Page1 / 5

Problem set 3 Crib 2011 - Chapter 2: Exercises 2.3b,...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online