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Unformatted text preview: 7.0581346 7.01600 = .0421346 amu. E= m(931.49)/total number of nucleons = (.0421346)(931.49)/7 = 5.606 MeV/nucleon C. Xenon has a number of stable isotopes; in fact, only two in the following string are radioactive. One decays by electron capture with a half life of 36.4 d, and the other decays by electron (beta) emission with a half life of 5.2 d. Identify the two isotopes from the list most likely to decay, predict the pathway of decay for each, and write a balanced equation. Briefly, explain your reasoning. 126 Xe 127 Xe 128 Xe 129 Xe 130 Xe 131 Xe 132 Xe 133 Xe 134 Xe Expect highest and lowest N/Z ratios with N=odd number to be radioactive. Therefore, 127 and 133 are radioactive. -1 e + 127 Xe 127 I + 133 Xe 133 Cs + -1 e +...
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- Spring '10