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Unformatted text preview: Calculations C pb = (m cal x c cal x ΔT cal +m w x c w x T w ) / (m pb x ΔT pb ) {Specific head of water is 1.00g/°C, calorimeter/stirrer.22 cal/g°c} C pb= (85g x .22 cal/g°C x 1.3°C + 177.5g x 1.00 cal/g°C x 1.3°C)/ (93g x 73.6°C)= .0373 Theoretical Value= .0305 Actual Value= .373 Percent Error: .037.0305/.0305= 22.2950% Data: Lead Calorimeter/stirrer Water Mass (g) 93g 85g 177.5g Initital temperature (C°) 97°C 22.1°C 22.1°C Final Temperature (°C) 23.4°C 23.4°C 23.4°C ΔT (°C) 73.6°C 1.3°C 1.3°C Specfic heat (cal/g°C) .0373 cal/ g°C .22 cal/g°C 1.00 cal/g°C Conclusion: In conclusion after heating the 93grams cups of metal (lead) in a steam generator and heating it to 95100°C the calorimeter/stirrers/and water absorbed the head. Based on the experimentation the specific heat of lead was .037 cal/ g°C meaning it takes this specific amount of heat to raise 1g of lead by 1°C. The experiment produced a percent error of 21.31%....
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 Spring '12
 Dues
 Thermodynamics, Absolute Zero, Heat, Thermodynamic temperature, specific head capacity

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