Ch5-HW3-solutions

# Ch5-HW3-solutions - louey (cal2859) Ch5-HW3 florin (56930)...

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Unformatted text preview: louey (cal2859) Ch5-HW3 florin (56930) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points After the NEAR spacecraft passed Mathilde, on several occasions rocket propellant was ex- pelled to adjust the spacecrafts momentum in order to follow a path that would approach the asteroid Eros, the final destination for the mission. After getting close to Eros, further small adjustments made the momentum just right to give a circular orbit of radius 45 km around the asteroid. So much propellant had been used that the final mass was 500 kg and it of the spacecraft took 1 . 04 days to make one complete circular orbit around Eros. Cal- culate what the mass of Eros must be. Use G = 6 . 67 10 11 N m 2 / kg 2 . Correct answer: 6 . 68001 10 15 kg. Explanation: We begin to solve this problem by equating the net force on NEAR and the gravitational force from Eros on NEAR: vextendsingle vextendsingle vextendsingle vector F net vextendsingle vextendsingle vextendsingle = vextendsingle vextendsingle vextendsingle vector F grav vextendsingle vextendsingle vextendsingle m | vectorv | 2 R = GM m R 2 | vectorv | 2 = GM R . The speed of the spacecraft is given by v = 2 R/T . Substitute this to get an ex- pression that relates the period and radius of the spacecrafts orbit. parenleftbigg 2 R T parenrightbigg 2 = GM R 4 2 R 2 T 2 = GM R T 2 = 4 2 GM R 3 . The above expression is known as Keplers third law for circular orbits. Solving for the mass of Eros, we have M = 4 2 R 3 GT 2 = 4 2 (45 km) 3 G (1 . 04 days) 2 = 6 . 68001 10 15 kg ....
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## This note was uploaded on 03/20/2012 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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Ch5-HW3-solutions - louey (cal2859) Ch5-HW3 florin (56930)...

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