Exam #1 (A) - A Math 201 Test 1 A ‘ Section Name O(Vt/1L...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: A . Math 201 - Test 1 A ‘ Section: Name: O (Vt/1L \ wj In problems 2 and 3 below indicate your choice by circling the correct solution . Work will not be graded. Work will not be graded on problem 14 as well. For all other problems, show appropriate work on the test page to receive credit and place your answer in the blank or space provided. Point value of each problem is given with the problem statement. Calculators are not allowed on this exam. Formulas you 1 2 2 may need on this exam: n—(nJr—) , W , ’1 ("4+1) 2 l. Solve for the variable in each equation below : (5 points each) a)2_t__1 : 6—,:3 __r_ 1’ it t j i 2 5 10 / tot-S A_ it—b V i [(2 1 (0 [0 5 — ’ : 11% r b "t it? .3 e 4 u i : ’Zmi; ' “l: 8 z 1 _ 1 Mi; gcluiwh b.) x2 ~1 x+1 x_1 m <5 X-l Kai (HAM-1‘) v (7m \(va (>0 tiller) 9, : X-t a (Km) 55 7;. “'2, NR. X Lew Sng‘l’lSQLI ‘l’l’xig fizzux‘Il‘Vh 2. In the literal equation below, solve for t in terms of the remaining variables. -(5 points) (Circle the correct answer.) mt+gt=2(3+t) 6 6 6 6 Amm‘g' B)mg—z Clmg+2 mag—2 mm -~..t+05t: (ant m‘h ‘l‘fifvl'k : C t_ ~_____,_ t W” @433 C» " “(HHS/2, 3. The sum of the r00t(s), that is the solution(s), of the equation V x + 2 = x — 4 is: (5 points) (Circle the correct answer.) A)0 B)9 C)7\ D)5 E)—5 M21551 1 2% m : Mr o:(></7~‘)(><'7l 2 x” : XIV/lsxlw X12 W X27 xr-‘Iijflw 2’7“! o : le 51X t “l - “Gm! vii—'2‘} Omit 1.: i 1; \{P‘J Amie] SW6 :9 X: ‘7 ' 4. Solve forx: x4 — 8x2 + 15 = 0 (5 points) _7 ,3, , w (vwaflv/Slio \t 3? 7» N 3/ 5. In each application problem below represent all unknowns in terms of one variable, establish an appropriate equation and solve. Show all appropriate steps. (7 points each) a.) A homeowner needs to spray her trees to kill defoliating insects. She needs 128 ounces of a solution made up of 3 parts insecticide A and 5 parts of insecticide B. How many ounces of insecticide A should be used? Lojz X rtfwflar HC‘aQ Woo-i" WM ‘ 0me JA 3x +S>< : Izié #— g0 3% out/w» 6/, insax‘hc‘l'be. 13X : [2% p x: 3?: Ito '5 3X ""7"" W b.) A company’s revenue from the sale of interior doors is $98 per door. The cost of producing the doors is $48 per door with $12, 000 in fixed costs. How many doors must the company sell in order to break even? 0mm : trim-{W , Cos-l1; ( I : @smew' « (Vim/:45 Let-is 3r VtI/VMLK 2140 8L2“; HP)va wine/1A“ vawS PW» 3 O l QC f o : «Ax “(W/"00 3’ WM) )WLW X" C) )7, 00C) , . r (E. x; (2000 X: « b‘lO 6. Solve forxin each inequality below. State your solutions using interval notation. (5 points each) I g 6x — 2 1 y, (- pg / ] a>—g—s—; ZWX—%:'3 ’1” V W -} e W V5, pm a fiat/t 3 X ’ Q L( X i 8 cf ((9)013 i '3 X s: 7-H 2 —8 — (: -2. U “’W‘O) b.) x3 _4 LX'?) 13% W 2x_gr( iLf 9°} is i/ K g v ' 20 .7. Evaluate 213i . (3 points) 2 7 3 0 i=1 7/0 :m ; ; , E, I) '2’ II 10. I: 1'5 .Lb 17‘ 8. State the degree and leading coefficient of the polynomial function f (x) = ‘—‘_’_2x7 + 3x5 + 4. (1 point each) Leading Coefficient: “2— ‘ Degree: 7 9. Given the fimction g(x) = , find the domain of function g, g(0), g(1/2) and g(xz). Simplify your answer if needed. (2 points each) Domain: X?’ -l4 Ll git/L3; Lu 1 ~37- : -'/7 g(0)= O V7]_L( 7/ ‘ l/ Xi. g(1/2): 7 ADC? 5" [)5’: K g(x2)= x52! 10. Ifflx) = x2 + l and g(x) = x— 2 , find: (3 points each) L a.)‘(/+g)<x) : x31 ,L >02 : 234 xv. (MW): Li; 13-) (fXgXZ) I $41)!)(zg : go i: 0, (.i’suwn : Q ~ ‘L L 1. c.) f(g(x)) '- H m) basz 4 I x «wwm {/3le :2 " ' z E A _ 2 , d-) (8°f)(x) 1 §(1le\) t 3(K M) : XL) 1-1, (6L4 )(A) - x _ \ 11. Find the inverse of the function below if it exists, showing all appropriate steps. If the inverse doesn’t exist, so state. (Spoints) 1. 1><« 7 M t \/ ‘ A! _ Ar? "g/(X) 1) Inf—"Hwhné \/v)’—7 v 2X Z 2’ .Su £063 ill/toe Vi? 5 X / 1 mm moan/L. vi )(f 7 J3 (2‘) : -——- 7/ 12. Given the equation: = 5 — 2x2: (8 points) y r. y a.) Sketch the graph on the axes at right. b.) Identify the intercepts _ - r:— ‘ o x intercept: )cx .L—f/l 1 5} o y intercept: (O, S ) 0.) Based on your graph, is y a function of x? Z? 5 d.) If y is a function of x, is it one-to-one? p9 ’ l '13 WA is“ i" S d“ 3 e.) If y is a function of x, what are the domain and range? 0 Domain: «LIZ; X 0 Range: (” PO ) V39! C: Ski/Xi ’Z/UI i XL 1‘ KW: , so? X14}: \/ 1: g” 13. Graph the case defined function below on the axes provided. (4 points) x+1if0$x<7 WW {5 \M W lb 6”“ ‘l / Pr 21¢ //> »‘ MN“ . / , . . r’ , I 1 «7?.- , x , , 1 ., I, I ( ‘7? >0 t» I, \ r k, a 41 r L .21 ,..- if \{1 51/ \ / i l "I 14. Complete the table below indicating the types of symmetry of the graph of each equation. The first row is completed to illustrate an appropriate response. (1 point each cell) ‘— Etluation -axis_symmetty x-axis immetgy ofl'gi'n Mmetfl y = 5x NO NO YES y = x2 — 4 i _ _ Ye ; M 0 Ni ‘ 2 2 x + xy + y = t N N I, i6 3 y = x2 — 25 ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern