Lecture 5

# Lecture 5 - Lecture 5 pls-5.1 Constant Acceleration Motion...

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Lecture 5 pls-5.1 Constant Acceleration Motion Media: 1. Fendt Web site 2. Feather and ball bearing video 3. Ping-pong ball and tennis ball 1. 1D Constant Acceleration Motion Basic problem: An object with initial conditions ( ) 0 0 x x = , () x x v v 0 0 = moves such that its acceleration x a is constant What are ( ) t v x and () t x ? The solution is () t a v t v x x x + = 0 ( 1 ) () 2 0 0 2 1 t a t v x t x x x + + = ( 2 ) By combining Eqs. (1) and (2) to eliminate x a or t , one can also derive the following two equations: () () [] t t v v x t x x x + + = 0 0 2 1 (have eliminated x a ) ( 3 ) () () [] 0 2 0 2 2 x t x a v t v x x x + = (have eliminated t ) ( 4 ) x v 0 0 x x a

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Lecture 5 pls-5.2 Note: i. Eqs. (1) – (4) are know as the kinematics equations for constant-acceleration motion in 1D. ii. In most problems, the hardest part of the problem will be to find which one of these has all the quantities that you know and the one quantity that you wish to find. iii.
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## This note was uploaded on 03/26/2012 for the course PHY 1020 taught by Professor Kodera during the Fall '11 term at University of Florida.

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Lecture 5 - Lecture 5 pls-5.1 Constant Acceleration Motion...

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