HW 7 KEY - CHM 2046 HOMEWORK 7 Name __.—_..._ SEC in 7 TA...

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Unformatted text preview: CHM 2046 HOMEWORK 7 Name __.—_..._ SEC in 7 TA 1. Calculate AG° for these reactions at 25°C (Ag° = —RT an): (a) AgClts} 2 Ag+(aq) + Cl"(aq), using Ksp = 1.8x10‘10 Aw: ._ career _ *gll- fig ~ «am mxwmswa “0 ) q.- _. - _, 0i I .. c), S—EHQL ;.[é7 :Z‘vndb G0 := 57;: t::;6VL‘a/ (b) Ag+(aq) + 2NH3(aq) Z Ag(NH3)2+(aq), using Kf = 1.7x107 0 7- m; 2, ~ (Mm gmxzsazmsm) wig-4X10} .65‘ :2 —L .an 10" I l 7!- X j/m Go: _L//_. tj/M, : 2. Calculate, for H2C03(aq) Z C02(g) + H20(l) (at 25 °C) (a) AG° (See Appendix B for the necessary AG°f values.) 1 Q 5559: (“33%.9 — 151—,197. +613A12. L91 ' 1 w z w Fit/(’03 “‘9‘ ‘ a a: ._ .1 (b) K 1 9/— 56/4127“ AG g'bm‘ 3 _ +3.!‘irxl0 /M,o}_ r 3' (3 k " “(f ( 2.51CIJIWIK.LSK)“' 6‘04 z) K= Ziggfixlo (c) What are the units of concentration used to calculate each [...] in the equilibrium expression? H2CO3 in I!) (:02 in W H20 in -— (dz Estimate (to 1 SF) the pressure of C02 in a can of soda. Use thlS to solve the K expression for the molarity of H2C03. _ C{) ‘ :l K “(71,005) ’2?— CRwaj 9002 = 1 r m EH2CO3] = 9.07% 1:295] ghapter 20 Problems: 1, 2, 5, 10—12, 14, 28, 29, 40-42, 47, 52, 0. Chapter 21 Problems: 1, 7—10. I 3. Complete (using H20, 14", and OH‘) and balance these redox equations. Show half—reactions. Circle the 0A, box the RA. (a) VNO3' + —-> Ag" + N02 (acidic) .- + #9 + H), D WHfl’ 3114+ H‘s (b). + -—> Nri(OI-I)2' f Fe(OH)3_ (basic) @- L 1 ~ -2 . (c) - - + --> CifQ4 (begic) " ' ' 2‘? 01,77— + H H20 + 3,9,“— )xl Light—"’- SHD-‘pa. 1“ '3 (tr-[DIN], '7) 2 [watt—— _ (d) _ + @339 '--> $43” + 62 (acidic) 14‘ "- -l - ‘ Z. .. \ +2- x Jim-c. (512" + 6*” ’F “M - ’ M” * L’ W9) a d’lx l : fl + Ranq-fl‘i‘ $74157. (e) [E] + -—> 3; «~— gHfi' «+7 saw" "7‘ Ni 36]" —-,\. ([7. ...
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HW 7 KEY - CHM 2046 HOMEWORK 7 Name __.—_..._ SEC in 7 TA...

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