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homework 11

# homework 11 - montes(dam2772 Homework11 shih(56310 This...

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montes (dam2772) – Homework11 – shih – (56310) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points For the following types radio waves infared radiation visible light ultraviolet radiation gamma radiation of electromagnetic radiation, how do the wavelength, frequency, and photon energy change as one goes from the top of the list to the bottom? Wavelength Frequency Photon Energy 1. Decreases Decreases Increases 2. Increases Decreases Increases 3. Increases Decreases Decreases 4. Decreases Increases Increases cor- rect 5. Increases Increases Increases Explanation: The wavelength decreases from the top of the list to the bottom, so the frequency f = v λ increases, as does and the photon energy E = h f . 002(part1of3)10.0points Consider the four lowest energy levels shown in the diagram of a certain atom. n = 1 n = 2 n = 3 n = 4 How many spectral lines will result from all possible transitions among these levels? 1. 8 2. None of these 3. 4 4. 5 5. 6 correct Explanation: n = 1 n = 2 n = 3 n = 4 003(part2of3)10.0points Which transistion corresponds to the lowest- frequency light emitted? 1. n = 4 to n = 1 2. None of these 3. n = 3 to n = 2 4. n = 4 to n = 3 correct 5. n = 4 to n = 2 Explanation: The lowest frequency occurs going from n = 4 to n = 3. 004(part3of3)10.0points Which transistion corresponds to the highest- frequency light emitted? 1. n = 3 to n = 2 2. n = 4 to n = 3 3. None of these 4. n = 4 to n = 2

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montes (dam2772) – Homework11 – shih – (56310) 2 5. n = 4 to n = 1 correct Explanation: The highest frequency occurs going from n = 4 to n = 1. keywords: 005(part1of3)10.0points An electron is in the second Bohr orbit of hydrogen. Find the speed of the electron. The value of ¯ h is 1 . 05 × 10 - 34 J · s . The Bohr radius is 5 . 29 × 10 - 11 m. Correct answer: 1 . 08939 × 10 6 m / s. Explanation: Let : n = 2 , ¯ h = 1 . 05 × 10 - 34 J · s , m = 9 . 11 × 10 - 31 kg , and a 0 = 5 . 29 × 10 - 11 m (Bohr radius) .
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