Unformatted text preview: x between 0 and 2 cm. (i.e. take t=1 hour plot C vs. x. Repeat for t= 2 hours and t=3 hours. Put the plots on the same graph.) Take D=105 cm 2 /s and B=0.036 g/cm 2 . (c) The boundary conditions that result in Equation 5.5 are such that a constant concentration of stuff (A) is maintained at its surface. Plot the concentration profile solution given by Equation 5.5 for t=1 hour, t=2 hours and t=3 hours for x between 0 and 2 cm. As in (b) put these 3 plots on the same graph (but not on the graph you produced in (b)). You should end up with two graphs (one for (b) and one for (c)) each with 3 curves. Take D=105 cm 2 /s and C s =0.036 g/cm 3 and C o =0 g/cm 3 . (d) Describe in words what you see in plots you produced in (b) and (c). Give your physical interpretation of why these plots look the way they do. 4) (10 pts) Callister 5.11. 5) (15 pts) Callister 5.15. 6) (15 pts) Callister 5.21. 7) (15 pts) Callister 5.26....
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 Spring '08
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 Chemistry, 1 Hour, 2 hours, 2 cm, 0 g, 0.036 g

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