Assignment___10__3.4_A_-_F - CIVE 335 Date 10/9/08...

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Unformatted text preview: CIVE 335 Date 10/9/08 Assignment # 10 Problem 3.4. A p. 83 NAME (Last, First) 3.4.A Draw the shear and bending moment diagrams and note all critical values for shear and moment. 16,000 lb 6' 10' = + + = 16,000 lb M = x 16')- (16,000 lb x 6') = x 16')- 96,000 ft-lb = x 16') = 96,000 ft-lb = 96,000 ft-lb / 16' = 6,000 lb +- 16,000 lb = 0 + 6,000 lb - 16,000 lb = 0- 10,000 lb = 0 = 10,000 lb 10,000 lb Shear Diagram + Maximum Shear =10,000 lb- Maximum Shear =- 6,000 lb-6,000 lb-6,000 lb 60,000 ft-lb Moment Diagram + Maximum Moment = 60,000 ft-lb Notes: 1 A simple beam is defined as a beam with only two (2) supports. 2 In simple beams, the shear passes through zero at some point between the supports on the shear diagram. 3 At zero shear, maximum moment occurs. 4 The area under the shear diagram is equal to the maximum moment. 5 With concentrated loads, or with uniformly distributed loads, the lines on a shear diagram are straight. 6. The Bending Moment diagram is represented by straight lines when concentrated loads occur, and with curved lines when uniformly distributed loads occur. = 10,000 lb x 6' = 60,000 ft-lb =- 6,000 lb x 10' =- 60,000 ft-lb Check: M (x = 16) = 60,000 ft-lb +- 60,000 ft-lb = F y = 0 F y R 1 R 2 R 1 R 2 R 1 R 2 R 1 (R 2 (R 2 (R 2 R 2 R 2 R 1 R 2 R 1 R 1 R 1 M (x = 0,6) M (x = 6,16) CIVE 335 Date 10/9/08 Assignment # 10 Problem 3.4. B p. 83 NAME (Last, First) 3.4.B Draw the shear and bending moment diagrams and note all critical values for shear and moment. w = 750 lb / ft . = + 14' + = 750 lb / ft x 14' = 10,500 M = x 14')- (750 lb / ft x 14') x 7 = x 14')- 73,500 ft-lb = x 14') = 73,500 ft-lb = 73,500 ft-lb / 14' = 5,250 lb +- (750 lb / ft x 14') = +- 10,500 lb = 0 + = 10,500 lb + 5,250 lb = 10,500 lb = 5,250 lb 5,250 lb Shear Diagram + Maximum Shear =5,250 lb- Maximum Shear =- 5,250 lb- 5,250 lb 18,375 ft-lb Moment Diagram + Maximum Moment = 18,375 ft-lb...
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Assignment___10__3.4_A_-_F - CIVE 335 Date 10/9/08...

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