Assignment___15__3.6_A_-_D - CIVE 335 3.6.A Due Date...

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CIVE 335 Due Date 10/28/2008 Assignment # 15 Problem 3.6 A p. 95 NAME (Last, First) 3.6.A Find the value for the maximum bending moment in the beam. 4 kips 4 kips + = 8 kips 8' 8' 8' = + ∑ M = 0 x 24') - (4 kips x 16') - (4 kips x 8') = 0 x 24') - 64 kip-ft - 32 kip-ft = 0 x 24') = 96 kip-ft = 96 kip-ft / 24' = 4 kips + - 8 kips = 0 + 4 kips -8 kips = 0 - 4 kips = 0 = 4 kips 4 kips Shear Diagram + Maximum Shear = 4 kips - " = - 4 kips - 4 kips 32 kip-ft Moment Diagram + Maximum Moment = 32 kip-ft = 4 kips x 8' = 32 kip-ft = 0 = constant = - 4 kips x 8' = - 32 kip-ft Check: = 32 kip-ft + - 32 kip-ft = 0 ∑ F y = 0 R 1 R 2 ∑ F y R 1 R 2 R 1 R 2 R 1 (R 2 (R 2 (R 2 R 2 R 2 R 1 R 2 R 1 R 1 R 1 M (x = 0,8) M (x = 8,16) M (x = 16,24) M (x = 0,24)
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CIVE 335 Due Date 10/28/2008 Assignment # 15 Problem 3.6 A p. 95 NAME (Last, First) 3.6.B Find the value for the maximum bending moment in the beam. w = 2.5 kips / ft + = (2.5 kips / ft x 18') =45 kips 18' = + ∑ M = 0 x 18') - (2.5 kips / ft x 18') x 9' = 0 x 18') - 405 kip-ft
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This note was uploaded on 03/27/2012 for the course CIVE 335 taught by Professor Desormeaux during the Spring '12 term at University of Louisiana at Lafayette.

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Assignment___15__3.6_A_-_D - CIVE 335 3.6.A Due Date...

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