hw3_soln

hw3_soln - Cgé’iéf’éO, gummay :0 Q‘ 11.51 Block C...

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Unformatted text preview: Cgé’iéf’éO, gummay :0 Q‘ 11.51 Block C moves downward with a constant velocity of 2 ft/s. De— termine (a) the velocity of block A, (b) the velocity of block D‘ m WT; m2 233 1 ‘3'“. S; a; ‘1; 357; a C‘ is“? .9“ ES) i a 13.3 C23 1 A i E j v Q s z « 1 3 fl ‘ gilt H M, 3 MD a («my «a3; gram) J. ‘ W‘rf’: #1 $32: * m i 5i" ; fir; a, 3 11.57 Slider block B moves to the left with a constant velocity of . 50 mm/s. At t = 0, slider block A is moving to the right with a constant ac— celeration and a velocity of 100 mm/s. Knowing that at t = 2 s slider block 70 has moved 40 mm to the right, determine (a) the velocity of slider block ‘ C at t = 0, (b) the velocity of portion D of the cable at t = 0, (c) the accel‘ erations of A and C. ' .. Fig. P1157 and P11g5§ ; i l I i , w l 22331 ' \ 1 wry t, “a > NE fit (5 g 0: ifiEggg‘E £43k: i 513" r If,» F n Egg; “El it: “g :3 l 2:55;” "2‘3 {xrmgloyjj 5’) 1 4019+301e QLQQA: Wifigq’g “O 3 X , _ R 15’ N05?) 3" Vfliwgfqaiolg awe +73 \4’ U" 5:5);CQL’EA‘JQ r « 35mg may—Larva fia’qfi Lg +¥€ a 2“ C0, Mai 15 L19 "ti/8 MU ] {t @ 34vew 0‘3: 505%“? {1694 (“33:0 / gm"? I . ; «3 1, M2? 49%,?“ 397% :IOHSU"? QC gar? C -» a; vigluefli SCCZQS we AGE/6 34mm 2, SCCZS)3C(7c)aE + GE: 35’? , 2; 'ZELCQZ] :iy m 2K3+Q£ ’39:”)?(2 2. 40mm) = 57% 9 11.59 Collar A starts from rest at t = 0 and moves upward with a con— stant acceleration of 3.6 in./s2. Knowing that collar B moves downward with a constant velocity of 18 in./s, determine (a) the time at which theveloeity i ' of block C is zero, (b) the corresponding position of block C. Fig. P1159 and P11.50 1' A!) ve(m%6t/acaim [grime 0x“ poem/tr owe «W8 \1/ 7 wacflm :7 0: (030+qu :27 L— mutt) 16 Greg} — (mo :QUO)02<2-§(r] + éac 26a?) : 7.5 @th {la Mode. (1 ...
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This note was uploaded on 03/22/2012 for the course CE 2460 taught by Professor Moorthy during the Fall '08 term at LSU.

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hw3_soln - Cgé’iéf’éO, gummay :0 Q‘ 11.51 Block C...

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