hw15_soln

hw15_soln - A f S C; 341/3531, Summer? 535 g; Mega”; $4)...

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Unformatted text preview: A f S C; 341/3531, Summer? 535 g; Mega”; $4) (I: 331:": 7 13.156 A 17.545 sphere A of radius 4.5 i 11. moving with a e: w z? ’ of magnitude 00 = 6 28/5 strikes a 1,6—Ib sphere B of radius 2 ‘ _ J”; [I a “£6 . . . . m W111 ~32 ‘3 i b at rest. Both spheres are hangmg from Identical hght flexible COT ‘ ing that the coefficient of restitution is 0.8, determine t he Veloci sphere immediately after impact. '3 :, ix fim/vc/La/s’éamcamefiduwwL 8 fizmj/ [jvcic‘y' O & DweoéeCw/‘mi Afimpaoé Cot/M? Z'dx‘r) eewam 13.176 A 2,5vlb Block B is mmng with a 'veiocity V0 of magnitude 30 t 6 ft/s as it hits the LES-lb sphere A, which is at rest and hanging from a Cmd’é attached at 0. Knowing that M = 06 between the block andt the horimm surface and e = 0.8 between the block and the sphere, determine after im pact, (a) the maximum height h reached by the sphere, (b) the distance traveled by the block. me, H ma 5% . a ’ 7‘ I Xv’difv", H fimfiodKeemamenMW WA‘Hg 01% MB L7; : Mfivgq’vr 61:) e «5:; +250; = Q . ww9€v¥ : [£6755] y4’+2«§6§5] I i <3 = %'UB “13"? t? i 0% .3” 43" /§ M (i 3 , i .f > [refil‘ :: at?" -—-—-‘ we 0:4 ts e :7 O‘QX‘é WE”%0 K g a 5535va [iQLZJ/ it} I 537§[%:) a; i:‘§"5§' e “We 5? 1w A fl i /' 5fca§re i CarveJ/pmds (“D diuséraééey Lm/saof-oé ‘Hoqzé‘l vaéjfémdg era‘iif ACU320) Wfl;é,m,cgl , .. ‘~ 2’ 1/ EfeéEZWKJ/iiv Z / 1 32a .fl’ L51] ":"O" a _ f -, "’ L. M, ‘ ,-. M @wgz;é°7§%)'tyi‘ H Tl; i‘MLgl; C} 9‘ OH 0:533” “W +87» (£549) [A an 7%] WM} “WW; :4sz r» we C£.£3”f€)“{“§‘fi :0 mr . i1: 09707 ' 8f Safe 1 WYEI/ycmdg 7L0 stofi/{L’f’ W‘fbaoé’ (Md Sink l (iWYéj/acmdg 71?; 333$ (Lip/QCEWP _ w {w T53L. '2. _ WES :5 '2 MM 1 2 7J2“? E5<""3:f/‘Wfi 5 Liz; 4.125% i " M, ‘ #w A 2, slag/C J/y g7}; 37 ': 0 iwa‘me) 5‘9 “Eng-mil; o Wig; Wags) up; 0,1121 : «M: N 161%ng N = Wig : 15(65)- : was“ 7: Lawn (x f6) :27”; :9; 0¢i48£€§»§£~)’/fi§125 [O [3 ; / 13.182 A 0.6—Ib 001131" A is released {rpm rest, slides down 3 fr}. less rod, and strikes a 1.8—ib coliar B which is at rest and suppofiedm ‘ spring of constant 34 lb/ft. Knowing that the coefficient of restituthn _ tween the two collars is 0.9, determine (a) the maximum distance 00H, ' moves up the rod after impact, (3)) the maximum distance collar 3 m; down the rod after impact. k = 34 Ib/f‘t 300 ivuir’gel rage #03550,“ {30 {415% fiéflfe imfaci“ ((31:02) a?» e w” : _L‘ g o a If L MA}? , 2.” «It; ’0 Tla‘g‘mflg’ (31...; r z. > 01.2,: Uch r" “WAC/W ‘6 7’1‘r01—223E-f5 > .. '2093 9;} ‘49:: o—rWMe) 3.25 a}; lo»77;£§: 5 5 Wired? (yak/<21 9mfad' 61(5) Z “div ' i // I *’ .9mf2cm/3e -mm1ewwfl far/4+ 8 a [Cs/36$ P”? “Ci/5"”; iqu : i475 “f” Mg, U}; v .I 41%) (5*) (23.3% x/m77[%): 5’8 + DJ ff 3» g y fl ‘ 5 VI, 3 i : 7 f6" W ‘ a, [13 ug +0 gar/q §:%(%) ( 3 3‘ 5’9}: 1,904; (gym, 2:}; ‘3 r4, 5&3}? 1. WYéific/nck +0 afier [m/getoé’ aeT 3,1,3”?! 6’2“ I (kg, 1 I B! a «fix-J’MXQ/Z M” f L 2 324; (Lb fl) f 05553 04913 61%? ~ [M (gm - a aang/“Z (3m; ~ éég‘z'IGJ’JJaéCfQ/i a 53/ "(IY§MA:§’O’?§max +974 r G x M845 (556/) 3‘9 (f 2m Ca “I m "@‘M 043%[15‘53 m" \\ Cr) ) , a , ~ ,‘ as ‘ 36g » “g! 1‘ 9 (wreffofi MOV’QM‘Qfl/é 6 ’ WW ...
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This note was uploaded on 03/22/2012 for the course CE 2460 taught by Professor Moorthy during the Fall '08 term at LSU.

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hw15_soln - A f S C; 341/3531, Summer? 535 g; Mega”; $4)...

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