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Unformatted text preview: 4.3QUS12 S8: An easy element of order 4 is (1234), so how to get others? We can put two disjoint 4 cycles together: (1234)(5678) We can also add a disjoint 2 cycles: (1234)(56), (1234)(56)(78) That's it. Any cycle length divides the order of the element, so an element of order 4 can have only 2 or 4 cycles. ...
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 Spring '12
 ankit
 Algebra

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