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Unformatted text preview: y & & 2 the horizantal asymptote. Third step changes the signs of y-intercept and horizantal asymptote. The last step makes y & & 3 the y-intercept and y & 3 the horizantal asymptote. It also affects the x-intercepts. The resulting graph is: 6 4 2-2-4-6 3 2 1-1-2-3 x y & 2 f & x /2 ± ± 1 Problem 2 (3 pts.) Prove the identity: log a & AB ± & log a & A ± ± log a & B ± Solution. Let’s say log a & A ± & x , log a & B ± & y , log a & AB ± & z . We want to show that x ± y & z . Rewrite logs as exponentials: a x & A , a y & B , a z & AB . Then we have a x a y & a x ± y & a z . Hence, x ± y & z and we are done....
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This note was uploaded on 03/24/2012 for the course MATHEMATIC 101 taught by Professor Many during the Spring '10 term at Sabancı University.
- Spring '10