quiz10-10.40-soln. - b. Evaluate the definite integral...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
MATH 101-B Fall 2004 Quiz 10 (10:40 – 12:30 Group) Dec. 17, 2004 Time : 15 minutes Name: ___________________ Student No: ___________ Follow the directions. No work = No credit!! Problem (6 + 4 pts) a. If = a xdx 0 3 cos , sin(-a) = ? Express your reasoning in words. Solution: Since cos is an even function: & - = 0 0 cos cos a a xdx xdx sin is an antiderivative of cos, so from FTC: 3 cos ) sin( ) 0 sin( 0 = = - - & - a xdx a Therefore sin(-a) = -3
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: b. Evaluate the definite integral & = + 1 ? ) 5 ( dx x x x Solution: We first find an antiderivative for the function in the integral, 3 2 5 ln 4 5 ln 1 2 / 3 1 5 ln 5 2 / 3 5 ln 5 5 2 / 3 5 ln 5 5 1 2 / 3 1 2 / 3 + =--+ = ± ± ² ³ ´ ´ µ ¶ + = ± ± ² ³ ´ ´ µ ¶ + + + = ± ± ² ³ ´ ´ µ ¶ + & & x dx x x C x dx x x x x x x...
View Full Document

This note was uploaded on 03/24/2012 for the course MATHEMATIC 101 taught by Professor Many during the Spring '10 term at Sabancı University.

Ask a homework question - tutors are online