HW 23 - benavides (jjb2356) homework 23 Turner (59130) 1...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: benavides (jjb2356) homework 23 Turner (59130) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points An air-core solenoid has a length of 73 . 3 cm, a cross-sectional area of 0 . 0687 m 2 , and contains 889 turns. The current through the solenoid increases by 9 . 58 A. The permeability of free space is 1 . 25664 10- 6 N / A 2 . By how much does the magnetic flux through the solenoid change? Correct answer: 1003 . 07 Wb. Explanation: Let : = 73 . 3 cm = 0 . 733 m , A = 0 . 0687 m 2 , N = 889 turns , I = 9 . 58 A , and = 1 . 25664 10- 6 N / A 2 . The magnetic field inside the solenoid is B = nI = (1 . 25664 10- 6 N / A 2 ) parenleftbigg 889 turns . 733 m parenrightbigg (9 . 58 A) = 0 . 0146007 T . B = B A = (0 . 0146007 T) (0 . 0687 m 2 ) = 0 . 00100307 Wb = 1003 . 07 Wb . 002 (part 1 of 2) 10.0 points Two separate loops each with the same radius and a current, in the directions shown, whose centers lie on the same axis perpendicular to the plane of the loops. 24 cm radius 139A 139A 7 . 2 m This figure is not to scale. The loop radii are small com- pared to the distance between the loops. Note: The left-hand side of the circular loops are closer to you. What approximately is the magnetic flux enclosed by the left loop due to the current in the right loop. Correct answer: 2 . 43889 10- 9 Wb. Explanation: a radius I I Let : a = 24 cm , = 7 . 2 m , and I = 139 A . The magnitude of the magnetic field at the axis of a loop carrying a current I , if is much larger than a is given by B = 2 3 = I a 2 2 3 = 2 bracketleftBig 4 bracketrightBig I a 2 3 , where the magnetic dipole moment = I A = I a 2 . The magnetic field at the left hand loop due to the right hand loop is nearly constant and parallel to the axis. Thus the magnetic flux from this field is benavides (jjb2356) homework 23 Turner (59130)...
View Full Document

Page1 / 5

HW 23 - benavides (jjb2356) homework 23 Turner (59130) 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online