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Unformatted text preview: benavides (jjb2356) – homework 32 – Turner – (59130) 1 This printout should have 10 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points In an LR circuit, a 102 V( rms ), 38 Hz source is in series with a 15 mH inductor and a 22 Ω resistor. What is the maximum rms current? Correct answer: 4 . 57612 A. Explanation: Let : f = 38 Hz , L = 0 . 015 H , R = 22 Ω , and V rms = 102 V . The inductive reactance is X L = ω L = 2 π f L = 2 π (38 Hz) (0 . 015 H) = 3 . 58142 Ω . The impedance of an RL circuit is the same as that of an RLC circuit, but without the capacitive reactance. Namely Z = radicalBig R 2 + X 2 L = radicalBig (22 Ω) 2 + (3 . 58142 Ω) 2 = 22 . 2896 Ω . The rms current is I rms = V rms Z = 102 V 22 . 2896 Ω = 4 . 57612 A . 002 (part 2 of 3) 10.0 points What is the power factor? Correct answer: 0 . 987007. Explanation: The phase angle in an RL circuit is the same as that of an RLC circuit, but without the capacitive reactance. Namelythe capacitive reactance....
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This note was uploaded on 03/26/2012 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner
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