# Mathcad - 01-01 - ⋅ = W e P e t ⋅ = P e 0.4kW = P e...

This preview shows page 1. Sign up to view the full content.

v 89.122 mi hr = converting to mph: v 39.841 m s = which yields: v 2 W e M = solving for the velocity: W e 1 2 M v 2 = so: W ke W e = but W ke 1 2 M v 2 = M 907.185kg = M 2000 lb 1 kg 2.205 lb = M 2000 lb = The kinetic energy in the car is given by 0.5Mv 2 W e 7.2 10 5 × J = W e 0.4 kW 30 min 60 sec min
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ⋅ = W e P e t ⋅ = P e 0.4kW = P e 20.0 A ⋅ ( ) 2 1 ⋅ Ω ⋅ = P e I 2 R ⋅ = t 30 min ⋅ = I 20.0 A ⋅ = R 1 Ω ⋅ = First find the energy dissipated in the resistor: Problem 1-1...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern