Mathcad - 01-01

Mathcad - 01-01 - ⋅ = W e P e t ⋅ = P e 0.4kW = P e...

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v 89.122 mi hr = converting to mph: v 39.841 m s = which yields: v 2 W e M = solving for the velocity: W e 1 2 M v 2 = so: W ke W e = but W ke 1 2 M v 2 = M 907.185kg = M 2000 lb 1 kg 2.205 lb = M 2000 lb = The kinetic energy in the car is given by 0.5Mv 2 W e 7.2 10 5 × J = W e 0.4 kW 30 min 60 sec min
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Unformatted text preview: ⋅ = W e P e t ⋅ = P e 0.4kW = P e 20.0 A ⋅ ( ) 2 1 ⋅ Ω ⋅ = P e I 2 R ⋅ = t 30 min ⋅ = I 20.0 A ⋅ = R 1 Ω ⋅ = First find the energy dissipated in the resistor: Problem 1-1...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.

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