Unformatted text preview: ( ) 2 ⋅ = W e 1 2 C ⋅ V pk 2 ⋅ = The energy stored in the electric field is given by: V pk 11.27kV = V pk 2 V rms ⋅ = The voltage is the RMS value, so the peak voltage is the RMS times the square root of 2. Solution: C 41.6 μ F ⋅ = V rms 7.97 kV ⋅ = Given: Problem 13...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
 Spring '12
 Piller

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