Unformatted text preview: 5 × J = which yields W pe M g ⋅ h ⋅ = The potential energy is g 9.807 m s 2 = The gravitational constant is: h 304.8m = h 1000 ft ⋅ 1 m ⋅ 3.281 ft ⋅ ⋅ = Solution: h 1000 ft ⋅ = M 70 kg ⋅ = Given: First we need to find the potential energy obtained by going to the top of the building: Problem 15...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
 Spring '12
 Piller

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