Mathcad - 01-07 and 08

Mathcad - 01-07 and 08 - Problem 1-7 : The average power...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Coal 9.598 10 7 × ton = Coal 2.133 45000000 ton := c. From Table 1-1, one Quad is 45 million tons of coal Thus the input energy is 2.133 Quads W in 2.133 10 15 × BTU = W in 2.25 10 18 × J = W in W elec eff := eff 0.28 := b. The utility generates 20,000 MW on average P avg 2.003 10 4 × MW = P avg W elec hours := hours 8.736 10 3 × hr = hours 52 wk 7 day wk 24 hr day := W elec 1.75 10 () 11 kW hr := Problem 1-7 : The average power for the year is the total energy delivered divided by the number of
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

Mathcad - 01-07 and 08 - Problem 1-7 : The average power...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online