Coal9.598107×ton=Coal2.133 45000000⋅ton⋅:=c. From Table 1-1, one Quad is 45 million tons of coal Thus the input energy is 2.133 QuadsWin2.1331015×BTU=Win2.251018×J=WinWeleceff:=eff0.28:=b. The utility generates 20,000 MW on averagePavg2.003104×MW=PavgWelechours:=hours8.736103×hr=hours52 wk⋅7⋅daywk⋅24⋅hrday⋅:=Welec1.7510()11⋅kW⋅hr⋅:=Problem 1-7: The average power for the year is the total energy delivered divided by the number of
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