Unformatted text preview: P gin 144.196hp = P gin 107.5 kW ⋅ 1 hp ⋅ 0.746 kW ⋅ ⋅ = So the engine must provide 107.5 KW at the shaft. There are 746 W/hp  converting to HP yields: P gin 1.075 10 5 × watt = P gin P gout η = η 0.93 = P gout 100 kW ⋅ = At rated output, the power out of the generator is 100 KW. Since we are given the efficiency, we can solve for the power into the generator: Problem 19 :...
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 Spring '12
 Piller
 Energy, Power, Watt, Imperial units, Joule

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