Mathcad - 01-09 - P gin 144.196hp = P gin 107.5 kW 1 hp...

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per hour Gallons 8.386gal = the number of gallons of gas required per hour Gallons W gas Gas = Gas 125000 BTU gal = One gallon of gas provides 125,000 BTUs: which is the amount of energy required in one hour W gas 1.048 10 6 × BTU = Converting to BTUs: W gas 1.106 10 9 × joule = W gas P ein 3600 sec = In one hour, there are 3600 seconds, so the energy provided by the gasoline in one hour is: P ein 3.072 10 5 × watt = P ein 107.5 kW 0.35 = P ein P gin η e = η e 0.35 = Since the engine is only 35% efficient, we can find the input power to the engine:
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Unformatted text preview: P gin 144.196hp = P gin 107.5 kW 1 hp 0.746 kW = So the engine must provide 107.5 KW at the shaft. There are 746 W/hp - converting to HP yields: P gin 1.075 10 5 watt = P gin P gout = 0.93 = P gout 100 kW = At rated output, the power out of the generator is 100 KW. Since we are given the efficiency, we can solve for the power into the generator: Problem 1-9 :...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.

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