arg Zload(2960-deg=Zload8.501Ω=Zload4.257.362i-Ω=ZloadVphIph=d. The impedance is found by dividing the voltage by the current in phasor notationI = 14.14 at -30 degreesV = 120.2 at -90 degreesc. The cosine leads the sine by 90 degrees, so changing the reference to cosine will subtract 90 degrees from each phasor in part b.Iph14.14 ej 60⋅deg⋅⋅amp⋅=I = 14.14 at 60 degreesIrms14.142=IrmsIpk2=Ipk20=Vph120.2 ej 0⋅deg⋅⋅volt⋅=V = 120.2 at 0 degreesVrms120.208=VrmsVpk2=Vpk170=b. Phasors are alway rms for the magnitude. If sin(ϖt) is the reference, then the phase angles are the same as in part a. So the phasors are:i(t) = 20 sin (ϖt + π/3) ampsThe current has a peak value of 20 amps and is leading the voltage by 60 degrees or
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