Unformatted text preview: = P V 2 R = a. The real power will only be disipated in the resistor. Since this is a parallel load, we can write: V 240 V ⋅ = X C 13-Ω ⋅ = R 20 Ω ⋅ = P2-4. Consider a parallel R-C circuit with R = 20 Ω and -jX C = -j13 Ω , with an applied voltage of 240 p o V. a. Calculate the real, reactive, and apparent power b. Calculate the total current from the source and the resistor and inductor currents....
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- Spring '12
- Electrical resistance, Itot, 2.88 kW, 4.431j, 18.462j, 56.976 deg