Unformatted text preview: C ⋅-= Since this is a series circuit, we need to find the total impedance and then solve for the circuit current Solution: V 240 V ⋅ = X C 9 Ω ⋅ = R 15 Ω ⋅ = P2-5. Consider a series R-C circuit with R = 15 Ω and -jX C = -j9 Ω , with an applied voltage of 240 p o V. a. Calculate the real, reactive, and apparent power b. Calculate the total current from the source and the resistor and capacitor currents....
View Full Document
This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
- Spring '12