Unformatted text preview: C ⋅-= Since this is a series circuit, we need to find the total impedance and then solve for the circuit current Solution: V 240 V ⋅ = X C 9 Ω ⋅ = R 15 Ω ⋅ = P2-5. Consider a series R-C circuit with R = 15 Ω and -jX C = -j9 Ω , with an applied voltage of 240 p o V. a. Calculate the real, reactive, and apparent power b. Calculate the total current from the source and the resistor and capacitor currents....
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- Spring '12
- Resistor, Electrical impedance, Apparent power, total current, series r-c circuit, capacitor currents