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Unformatted text preview: V 120.208volt = V 170 2 volt ⋅ = a. In phasor form, the magnitude is given by Problem 2-6: Solution S 1.112 10 3 × volt amp ⋅ = reactive Q 1.026 10 3 × volt amp ⋅ = Q Im S ( ) = P 427.515 watt = P Re S ( ) = where S 427.515 1.026j 10 3 × + watt = S V I ⋅ = d. Find the complex power: Sum 120.208volt = Sum V R V L + V C + = As a check, add the voltages The capacitor voltage is 90 o behind the resistor voltage and the magnitude of the capacitor voltage is coincidentally the same as the source voltage arg V C ( 29 157.38-deg = V C 120.208volt = V C 110.961-46.234j-volt =...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.
- Spring '12