Unformatted text preview: then solve for the line current. Recall that the phase voltage lags the line voltage by 30 deg Solution: V AB 240 V ⋅ = X C 9 Ω ⋅ = R 15 Ω ⋅ = P2-12. Three of the series-connected impedances of P2-5 are connected in a three-phase, wye load. A balanced, three-phase set of voltages is applied to the load, and V AB = 240 p o V. Calculate the total, three-phase real, reactive, and apparent power....
View Full Document
This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
- Spring '12