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Unformatted text preview: = X C 9 = V AB 240 V = Solution: Since this is a delta-load with a series impedance, we need to find the total impedance and then solve for the phase current. Recall that the phase current leads the line current by 30 deg Z R j X C -= Z 15 9j- = define kVA kW kVAR kW V ph V AB = V ph 240V = arg V ph ( 29 0deg = I ph V ph Z = I ph 11.765 7.059j + A = I ph 13.72A =...
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- Spring '12