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Unformatted text preview: constant. Therefore, solve for the real power Solution F pnew 0.93 = F pold 0.76 = S load 232 kVA = Given: kVAR kW kVA kW Define: P2-23. A machine shop has a three-phase electrical load consisting of many small motors. The total shop load is 232 KVA and the power factor is 0.76 lagging. The utility would like them to improve their power factor to greater than 0.93 lagging, but they must keep a lagging power factor. How many KVARs of capacitors will they require to achieve the minimum power factor....
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.
- Spring '12