Mathcad - 02-24 - An industrial load consists of the...

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P o3 215 hp := P o3 22.371 kW = η 3 0.92 := F p3 0.85 := P o4 300 hp 0.75 := P o4 167.782 kW = η 4 0.92 := F p4 0.85 := P L 50 kW := Since the power factors are given for each load, we can find the phase angle of each. Of course, the lighting load has an angle of zero. θ 1 acos F p1 () := θ 2 acos F p2 := θ 3 acos F p3 := θ 4 acos F p4 := θ 1 45.573deg = θ 2 36.87deg = θ 3 31.788deg = θ 4 31.788deg = Problem 2-24: An industrial load consists of the following: 1 - 50 hp induction motor with ç = 86% and pf = 70% lagging. (fully loaded) 1 - 100 hp induction motor with ç = 89% and pf = 80% lagging. (82% loaded) 2 - 15 hp induction motor with ç = 92% and pf = 85% lagging. (fully loaded) 1 - 300 hp induction motor with ç = 92% and pf = 85% lagging. (75% loaded) 50 kW incandescent lighting load. A synchronous motor is to be added. It is 60% loaded and rated 300 kVA, 80% leadin power factor. Determine the following: (a) Total plant real power. (b) Total plant reactive power. (c) Total plant apparent power. (d) Total plant power factor. define KVA kW KVAR kW Solution First find the actual load for each motor output power including loading% HP times 0.746 gives
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.

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Mathcad - 02-24 - An industrial load consists of the...

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