This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: I n 185.54amp = I n 3 I 3 2 I 9 2 + I 15 2 + ⋅ = f. In a three phase system, the neutral will carry the third, ninth, and fifteenth harmonics which add together from the three phases. RMSing them together yields: F pdist 0.861 = F pdist F ptot F pdisp = from equation 3.17 we could also note that the distortion power factor is given by the ratio of the total power factor to the displacement power factor F pdist 0.861 = F pdist 1 1 THD F 100 2 + = (in percent) THD F 100 THD 1 ⋅ = e. We can find the distortion power factor from equation 3.19 lagging F ptot 0.619 = F ptot P S = from equation 3.15: S 16.167kVA = S V 1 I rms ⋅ = NOTE: There is only one component for the voltage d. To find the total power factor, we know P and can find S...
View
Full Document
 Spring '12
 Piller
 Volt, Power factor, AMP, Irms, Total harmonic distortion

Click to edit the document details