Mathcad - 03-06 - 1 9 2 ⋅ = h 7 1 7 2 ⋅ = h 5 1 5 2 ⋅...

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THD R 41.036% = or THD R 0.41 = THD R rms h RMS = RMS 0.775 = RMS h 1 2 rms h 2 + = For THD R , we need the rms of all eight terms. We already have the rms of the last 7, so just rms the fundamental with it THD F 44.999% = or THD F 0.45 = THD F rms h h 1 = For THD F , we divide by the fundamental rms h 0.318 = rms h h 3 2 h 5 2 + h 7 2 + h 9 2 + h 11 2 + h 13 2 + h 15 2 + = For both THD values we need the rms of the harmonics other than the fundamental h 15 1 15 2 = h 13 1 13 2 = h 11 1 11 2 = h 9
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Unformatted text preview: 1 9 2 ⋅ = h 7 1 7 2 ⋅ = h 5 1 5 2 ⋅ = h 3 1 3 2 ⋅ = h 1 1 2 = The terms of the series are of the form 1/n where n is an odd integer, thus the rms values are: Solution Calculate the THD R and THD F for a square wave using the first eight terms of the series in equation 3-2. Problem 3-6: Solution...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University.

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