# Mathcad - 04-06 - Problem 4-6 Solution R:= 65 ohm Givens 2...

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reluct gap μ 0 A c = reluct 6.897 10 5 × amp weber = Reluct tot reluct reluct c + = Reluct tot 6.926 10 5 × amp weber = MMF g Flux reluct = MMF c Flux reluct c = MMF g 931.056amp = MMF c 4.011amp = MMF tot MMF c MMF g + = MMF tot 935.067amp = I MMF tot N = I 2.338amp = H gap B μ 0 = H gap 1.432 10 6 × amp m = H core B μ r μ 0 = H core 14.324 amp m = The field intensity is much lower in the steel due to the high relative permeability of the steel Problem 4-6: Solution Givens: R 65 ohm = N 400 = A c 0.00075 m
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