reluct
gap
μ
0
A
c
⋅
=
reluct
6.897
10
5
×
amp
weber
=
Reluct
tot
reluct
reluct
c
+
=
Reluct
tot
6.926
10
5
×
amp
weber
=
MMF
g
Fluxreluct
⋅
=
MMF
c
Fluxreluct
c
⋅
=
MMF
g
931.056 amp
=
MMF
c
4.011 amp
=
MMF
tot
MMF
c
MMF
g
+
=
MMF
tot
935.067 amp
=
I
MMF
tot
N
=
I
2.338 amp
=
H
gap
B
μ
0
=
H
gap
1.432
10
6
×
amp
m
=
H
core
B
μ
r
μ
0
⋅
=
H
core
14.324
amp
m
=
The field intensity is much lower in the steel due to the high relative permeability of the steel
Problem 46:
Solution
Givens:
R
65 ohm
⋅
=
N
400
=
A
c
0.00075 m
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
 Spring '12
 Piller

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