reluct gap μ0 A c ⋅ = reluct 6.897 10 5 × amp weber = Reluct tot reluct reluct c + = Reluct tot 6.926 10 5 × amp weber = MMF g Fluxreluct ⋅ = MMF c Fluxreluct c ⋅ = MMF g 931.056 amp = MMF c 4.011 amp = MMF tot MMF c MMF g + = MMF tot 935.067 amp = I MMF tot N = I 2.338 amp = H gap B μ0 = H gap 1.432 10 6 × amp m = H core B μ r μ0 ⋅ = H core 14.324 amp m = The field intensity is much lower in the steel due to the high relative permeability of the steel Problem 4-6: Solution Givens: R 65 ohm ⋅ = N 400 = A c 0.00075 m
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.