{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Mathcad - 04-13

# Mathcad - 04-13 - respective flux densities 0 0.2 0.4 0.6...

This preview shows page 1. Sign up to view the full content.

I coil 1.84 A = I coil F tot N := The current is the mmf divided by the number of turns F tot 552 turns A = F tot F cs F ci + := The total mmf is the sum of the two F ci 160 A = F cs 392 A = F ci l ci H ci := F cs l cs H cs := We can find the mmf required for each portion of the core by multipying field intensity times length H ci 800 A turns m := H cs 560 A turns m := From the B-H curves, we can obtain the field intensity for the two materials at their
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: respective flux densities 0 0.2 0.4 0.6 0.8 1 1.2 1.4 600 800 1000 Cast Iron Cast Steel Sheet Steel H in At/m 0 200 400 B ci 0.3 T ⋅ := B cs 0.75 T ⋅ := N 300 turns ⋅ := l ci 0.2 m ⋅ := l cs 0.7 m ⋅ := Problem 4-13: Solution turns 1 ≡...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online