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# êµ¬ì¡°ì—­í•™ë°_ì‹¤í

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? ? ? ? ?  ? ? Problem Solution – Homework #2 ? ? ? ? ? ? ? ? ? ? ? ? 2.1 Solution: a. Deformed shape b. Strain components c. Volume Change , since 2.2 Solution: Finding rigid body rotation by taking the average rotation of two adjacent sides. If the deformation is small enough, 2.3 Solution:

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2.4 Solution: Transformation of x and y Express in u and v terms Then we get for x and y Substitute to u and v equations Substitute the values of and into the and equation 2.5 Solution: Since, 2.9 Solution: Isotropic

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2.11 Solution: a. Plane strain conditions Since, b. Plane stress condition Since, 2.12 Solution: Three dimensional stress-strain relations can be expressed as:
a. Aluminum alloys are usually considered isotropic, so the above three-dimensional stress-strain relations can be utilized. Also, we have the mechanical properties for aluminum 2024 T3: E= 72 GPa, υ = 33.0. b. If the lateral surface of the bar is not allowed to contract during loading, we have the conditions: So we can use

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c. Compare with the corresponding load for the bar under simple tension. Under
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## This note was uploaded on 03/25/2012 for the course AEROSPACE 301 taught by Professor Pfchang during the Spring '12 term at Shandong University.

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