This preview shows page 1. Sign up to view the full content.
Unformatted text preview: I lsec 62.354 44.504j amp = I lsec V s1 Z lsec ( ) := since the voltage is 240: Z lsec 2.55 j 1.82 + ( ) ohm := V prated 7200 volt := V s1 240 volt := Problem 5-2 Solution: The load on the above transformer is 2.55+j1.82 ohms at the 240 volt terminals. Find P and Q to the load, the input impedance of the transformer and load, and the KVAR rating of a capacitor to correct the load to unity power factor....
View Full Document
- Spring '12