Mathcad - 05-03abcd - Problem 5-3 a,b,c,d: solution S :=...

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Q sc 694.556KVAR = X eq Q sc I sc 2 = R eq 16.54 = X eq 132.285 = c. find efficiency when load is rated at unity power factor F p 1.0 = P cu P sc = P core P oc = P out S F p = P loss P cu P core + = P loss 161.84kW = η P out P out P loss + = η 98.407% = d. find efficiency when load is rated at 0.8 power factor F p 0.8 = P cu P sc = P core P oc = P out S F p = P loss P cu P core + = P loss 161.84kW = η P out P out P loss + = η 98.017% = Problem 5-3 a,b,c,d: solution Givens: S 10000 KVA = V p 138 kV = V s 7200 volt = V oc 7200 volt = V sc 9660 volt = I oc 20.8 amp = I sc 72.46 amp
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.

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