Mathcad - 05-03e - V srated 7200 volt ⋅ = and we found...

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V fl V s = The turns ratio is: a V prated V srated = a 19.167 = Referring the secondary voltage and current to the high side: V shs a V s = I shs I s a = V shs 1.38 10 5 × volt = I shs 72.464 amp = The primary voltage is the sum of the referred secondary voltage and the drop across the equivalent impedance of the windings: V p V shs I shs Z eqhs + = V p 139.198 9.587j + KV = V p 139.528KV = Referring the primary voltage to the low side yields the no-load voltage V pls V p a = V nl V pls = V nl 7.28 10 3 × volt = So Volt_Reg V nl V fl - V fl 100 % = Volt_Reg 1.107% = _______________________________________________________________________________ Problem 5-3e Solution : The step-down transformer is rated as follows: S rated 10000 KVA = V prated 138000 volt =
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Unformatted text preview: V srated 7200 volt ⋅ = and we found previously: Z eqhs 16.53 132.3j + ( ) Ω ⋅ = e. Find the voltage regulation of the transformer if it is delivering rated current at a rated voltage and a power factor of 1.0. Solution : First we must find rated current I srated S rated V srated = I srated 1.389 10 3 × amp = The actual current is at a power factor of 1.0, so the angle is: θ acos 1 ( ) = θ 0deg = and the current is: I s I srated cos θ ( 29 ⋅ I srated sin θ ( 29 ⋅ j ⋅-= I s 1.389 10 3 × amp = The actual secondary voltage is: V s 7200 volt ⋅ =...
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