X mp 24.262k Ω = X mp a 2 X m ⋅ = R fep 52.934k Ω = R fep a 2 R fe ⋅ = These values, however, are referred to the low side, so we must refer them to the high side X m 22.001 Ω = X m V oc 2 Q oc = Q oc 2.618kVAR = Q oc S oc 2 P oc 2-= S oc 2.88 kVA = S oc V oc I oc ⋅ = We can find the magnetizing reactance in a similar fashion, but first we must find the reactive power during the open circuit test R fe 48 Ω = R fe V oc 2 P oc = since P=V 2 R, we can solve for R The core loss resistance can be found using the open circuit test data.
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.