X
mp
24.262k
Ω
=
X
mp
a
2
X
m
⋅
=
R
fep
52.934k
Ω
=
R
fep
a
2
R
fe
⋅
=
These values, however, are referred to the low side, so we must refer them to the high side
X
m
22.001
Ω
=
X
m
V
oc
2
Q
oc
=
Q
oc
2.618kVAR
=
Q
oc
S
oc
2
P
oc
2

=
S
oc
2.88 kVA
=
S
oc
V
oc
I
oc
⋅
=
We can find the magnetizing reactance in a similar fashion, but first we must find the
reactive power during the open circuit test
R
fe
48
Ω
=
R
fe
V
oc
2
P
oc
=
since P=V
2
R, we can solve for R
The core loss resistance can be found using the open circuit test data.
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
 Spring '12
 Piller

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