Xeqs0.035Ω=XeqsXeqa2:=Reqs8.705103−×Ω=ReqsReqa2:=These values, however, are referred to the high side; we can also refer them to the low sideXeq38.831Ω=XeqQscIsc2:=Qsc6.067 kVAR=QscSsc2Psc2−:=Ssc6.25 kVA=SscVscIsc⋅:=We can find the equivalent reactance in a similar fashion, but first we must find the reactive power during the open circuit testReq9.6Ω=ReqPscIsc2:=since P=I2R, we can solve for RThe equivalent resistance can be found using the short circuit test data.
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.