Mathcad - 05-10

Mathcad - 05-10 - kVA kW kVAR kW Problem 5-10 Solution...

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X eqs 0.035 = X eqs X eq a 2 := R eqs 8.705 10 3 ×Ω = R eqs R eq a 2 := These values, however, are referred to the high side; we can also refer them to the low side X eq 38.831 = X eq Q sc I sc 2 := Q sc 6.067 kVAR = Q sc S sc 2 P sc 2 := S sc 6.25 kVA = S sc V sc I sc := We can find the equivalent reactance in a similar fashion, but first we must find the reactive power during the open circuit test R eq 9.6 = R eq P sc I sc 2 := since P=I 2 R, we can solve for R The equivalent resistance can be found using the short circuit test data.
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.

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