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Unformatted text preview: 24.998kVA = i.e., 25 kVA kVA kW ≡ kVAR kW ≡ Problem 5-16: V prated 480 V ⋅ = V srated 240 volt ⋅ = Note: The given equivalent impedance is referred to the low side (secondary) Z eqs 0.062 j 0.105 ⋅ + ( ) Ω ⋅ = F p 0.87 = lagging I L 104.16 A ⋅ = Solution θ acos F p ( 29-= θ 29.541-deg = angle is negative since lagging F p The secondary load current is given in complex form by: I s I L e j θ ⋅ ⋅ = I s 90.619 51.356j-A =...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue.
- Spring '12